Bloomington Minnesota Valentine’s Day Giveaway
Win a $250 Mall of America gift card and a 3-night hotel stay in Bloomington
Bloomington Minnesota Travel & Tourism is offering a 2026 Valentine’s Day Giveaway where one lucky winner will enjoy a romantic getaway including a three-night stay for two at the Sheraton Bloomington Hotel and Lela Restaurant, plus a $200 Mall of America gift card valid at participating stores, restaurants, and attractions.
How to Enter
The giveaway runs from January 8, 2026, at 12:00 a.m. Central Time through February 11, 2026, at 11:59 p.m. Central Time. Participants aged 21 or older who reside in the United States or Canada (excluding Quebec) can enter by completing the online entry form on the official giveaway website, providing basic contact information and answering a hotel-related question. Only one entry per person per day is accepted.
A winner will be randomly selected around February 12, 2026, and contacted via email. The winner must comply with verification requirements including completing forms and providing valid ID. The prize must be redeemed on dates specified by the sponsor, and any additional travel expenses or taxes are the winner’s responsibility.
Official details and entry instructions are available on the Bloomington Minnesota Travel & Tourism website.
Love winning free prizes? Click here to explore all current Giveaway opportunities.
